(16u^6-12u^4)/4u^3

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Solution for (16u^6-12u^4)/4u^3 equation:


u in (-oo:+oo)

u^3*((16*u^6-(12*u^4))/4) = 0

u^3*((16*u^6-12*u^4)/4) = 0

(u^3*(16*u^6-12*u^4))/4 = 0

16*u^6-12*u^4 = 0

4*u^4*(4*u^2-3) = 0

4*u^2 = 3 // : 4

u^2 = 3/4

u^2 = 3/4 // ^ 1/2

abs(u) = (3/4)^(1/2)

u = (3/4)^(1/2) or u = -(3/4)^(1/2)

4*u^4*(u-(3/4)^(1/2))*(u+(3/4)^(1/2)) = 0

(4*u^3*u^4*(u-(3/4)^(1/2))*(u+(3/4)^(1/2)))/4 = 0

( 4*u^4 )

4*u^4 = 0 // : 4

u^4 = 0

u = 0

( u+(3/4)^(1/2) )

u+(3/4)^(1/2) = 0 // - (3/4)^(1/2)

u = -(3/4)^(1/2)

( u-(3/4)^(1/2) )

u-(3/4)^(1/2) = 0 // + (3/4)^(1/2)

u = (3/4)^(1/2)

( u^3 )

1*u^3 = 0 // : 1

u^3 = 0

u = 0

u in { 0, -(3/4)^(1/2), (3/4)^(1/2), 0 }

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